There exists a sequence of pointssuch that
as
and
![]()
Consider the polynomial![]()
with
. For n large compared to m, we will show that
has a zero near to
![]()
and
. We show that one can take
.
To show that
has a zero
near
, let
![]()
Then
. Consider the circle
. On this circle,
, while
![]()
so for
, by Rouché's theorem
and
have the same number of zeros inside the circle, namely one. This proves the claim and answers the Conway-Parker question.