Ifis compact,
, |z| < 1, and
![]()
then every element of B is expressible in the form
![]()
In particular, if
, then
.
If,
, then
.
Ifis compact,
,
,
and
![]()
where int
denotes the interior of S, then there is a neighborhood N of x such that
![]()
Iffor some
,
, |x| =1 and
![]()
then
![]()
If |x| =1,, then
.
Proving is trickier,
because it will not do to take B as a disc of radius
if
is small compared to
.
We will instead take B as a parallelogram that becomes flatter and flatter as
.
The following two lemmas will be used in verifying the condition of Lemma 3.1.
Let. Let
. Then for
![]()
![]()
contains
.
Let T,be as in Lemma 3.4. Let B be the square with vertices
. Then for
,
![]()
.
We now combine all the results of this section.
There is an open neighborhood ofcontained in
.
Iffor sufficiently small
then z is a multiple zero of some 0,1 power series.